Q Power 15s Subwoofer For Sale Can Anyone Help Me With Physics?
Can anyone help me with Physics? - q power 15s subwoofer for sale
Q: Can accelerate a mass of 120 kg from rest to 2.3 m / s in 15s. Meanwhile, friction exerts an average force of 45N.
What kind of work you have done for the masses? How much power?
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3 comments:
given the Acceleration = 2.3/15 = 0.153
given mass = 120 kg => = 120 * 0153 = 18.4 N for the force
given the strength to resist the friction is 45 N
Active population of 63.4 n =
Work = 63.4 * Travel
Power = work / time (or), 63,4 * The speed of the
The acceleration is 2.3/15, or 0.1533333
My strength is either 120 * 0.1533333 say, 18.4. This is the net force on the mass of the friction, so that the entire force is 18.4 = 45
63.4N
Working 1/2mv ^ 2 joules or 0.5 * 120 * 2.3 * 2.3 = 276
Power is work / time = 276 * 60/15 = 1104 watts
Work in mass = change in kinetic energy
Ec = (1 / 2) (120) (2.3) ^ 2
KE = 317.40 Joules
and power
P = 317.40/15 = 21.16 J / s = 21.16 watts
NOTE - other information not contained in the problem is required. Hope this helps.
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